Or you accept that if you're randomly losing chunks, you might lose an extra 3 bytes.
The real problem is that seeking a few bytes won't work with EMBL. If continuation bytes store 8 payload bits, you can get into a situation where every single byte could be interpreted as a multi-byte start character and there are 2 or 3 possible messages that never converge.
alt Hacker News
Okay so you seek by 3 less bytes.
Or you accept that if you're randomly losing chunks, you might lose an extra 3 bytes.
The real problem is that seeking a few bytes won't work with EMBL. If continuation bytes store 8 payload bits, you can get into a situation where every single byte could be interpreted as a multi-byte start character and there are 2 or 3 possible messages that never converge.