logoalt Hacker News

wedog6yesterday at 9:22 AM1 replyview on HN

This result is out from the article by a factor of pi/3. This is the multiplicative difference between his inner integral with all the sins 24pi^2 and the GP's observation that 3 points on the chosen circle have density (2 pi r)^3 = 8pi^3 r^3.

(The article had already covered the r^3 in another part of the calculation.)

I'm trying to figure out an intuitive explanation as to why the work with the inner Jacobian is needed or an argument as to why it isn't.

Anyone want to simulate this accurately enough to distinguish between 40% and 41.9% probability? 5000 samples should be more than enough.


Replies

quibonoyesterday at 10:45 AM

There's actually a second post on exactly that [0]

https://blog.szczepan.org/blog/monte-carlo/