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ogogmadtoday at 2:37 PM1 replyview on HN

I think you would get sqrt(x^2) = x, if x belonged to the natural domain of sqrt, which is a Riemann surface, that may also be defined using the language of "sheaves". I don't know how to connect this to the article or Mathematica.


Replies

mathisfun123today at 5:14 PM

it's literally the prototypical example for `Assuming`

https://reference.wolfram.com/language/ref/Assuming.html