alt Hacker NewsI mean don't modern CPUs basically just run an x86_64 emulator on a RISC machine anyway? Like there's a layer between the microcode and the actual x86 instructions already.
Replies
adwn • today at 11:21 AM
No, that's a myth. It's true that the instruction decoder in a CPU core translates from ISA opcodes to micro-ops for the backend, but those micro-ops are in many cases functionally very close to the ISA instruction and decidedly not RISC-like. For example, the ADD r/m64, imm32 instruction (read from memory, add constant, write to memory) is translated to a single micro-op on several Zen architectures [1], which is far from anything you could call "RISC".
raverbashing • today at 10:03 AM
I think it's more like a (kinda) VLIW machine but yes, pretty much
Yes, but the “architecture-independent” bytecode for these RISC machines that run underneath your various Intel and AMD CPU models is the x86_64 instruction set.