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flebron • today at 2:50 AM • 3 replies • view on HN

Note in this case the title says "O(n log n)", but the important part is this is "o(n log n)", not just "O(n log n)'. The former is a strict subset of the latter. We already knew how to multiply two n-bit integers in O(n log n) time, via the FFT.


Replies

ComplexSystems • today at 3:12 AM

Roughly speaking, O(n log n) means "grows no faster than k(n log n) for some k", whereas o(n log n) means grows strictly more slowly* than k(n log n) for all* choices of k.

onionisafruit • today at 2:55 AM

For those of us uninformed, what’s the difference between O and o?

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craigcitro • today at 2:58 AM

ty, fixed. (ahh, copy paste.)