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lg5689 • today at 5:59 AM • 1 reply • view on HN

Are you thinking of the int multiplication result instead? The DFT result uses a computation model with unlimited precision reals.


Replies

adgjlsfhk1 • today at 6:23 AM

no. The DFT result as published uses unlimited precision, but the comparison with the int multiplication shows that the unlimited precision just makes the paper shorter/easier rather than being an exploit in the computation model.